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16x^2+15x-7=0
a = 16; b = 15; c = -7;
Δ = b2-4ac
Δ = 152-4·16·(-7)
Δ = 673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{673}}{2*16}=\frac{-15-\sqrt{673}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{673}}{2*16}=\frac{-15+\sqrt{673}}{32} $
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